If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4x^2-8x+5=32
We move all terms to the left:
4x^2-8x+5-(32)=0
We add all the numbers together, and all the variables
4x^2-8x-27=0
a = 4; b = -8; c = -27;
Δ = b2-4ac
Δ = -82-4·4·(-27)
Δ = 496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{496}=\sqrt{16*31}=\sqrt{16}*\sqrt{31}=4\sqrt{31}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-4\sqrt{31}}{2*4}=\frac{8-4\sqrt{31}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+4\sqrt{31}}{2*4}=\frac{8+4\sqrt{31}}{8} $
| 2(x^+1/x^)-9(x+1/x)+14=0 | | -1+x+46=18x+5 | | 3t^2+8t=60 | | 90°+x+2x+3x=180° | | 5x+13=91 | | 8y+5y=7 | | X^2(2^x)-4(2^x)=0 | | X^22^x-4(2^x)=0 | | (X^2)(2^x)-4(2^x)=0 | | 4b-8-b=10b-b | | x.3=18 | | 3^(x^2)-42=1/(3^x) | | 15x=15*3 | | 3x2+92x-7200=0 | | 6d=2/1 | | w+0.02w=9.69 | | 8+ww=12 | | -1/2+3/7y=-1/3 | | 4∣y+1∣−16=0 | | 15+9v=60 | | n/7+77=82 | | 4X=-2y+14 | | u/4+16=18 | | -6×+10=4x+12+8 | | q-23/9=6 | | 2=m/7-3 | | 3(x+9)=16 | | j/4-9=3 | | j/4-9=1 | | 19=u/3+16 | | 4y−6y−24=30 | | 5+3x=10-6x |